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Focal chord of y 2 16x is a tangent

WebMar 14, 2024 · It is given that the focal chord is tangent to the circle which means that the distance of the focal chord from the center of the circle is equal to the radius of the circle. Therefore, we get m x − y − 4 m 1 + m 2 = 2 Now we will put the value of x = 6 and y = 0 in the above equation, we get ⇒ 6 m − 0 − 4 m 1 + m 2 = 2 WebGet an expert solution to The focal chord of the parabola ( y − 2 ) 2 = 16 ( x − 1 ) is a tangent to the circle x 2 + y 2 − 14 x − 4 y + 51 = 0 , then slope of the focal chord can be

The focal chord of \( y^{2}=16 x \) is tangent to \( \mathrm{P ...

WebMath Advanced Math If a focal chord of y =16x is a tangent to the circle (x-6)° +y² = 2, then the positive value of the slope of this chord is. If a focal chord of y =16x is a … WebHere, the focal chord of y 2 = 16 x is tangent to circle (x − 6) 2 + y 2 = 2 ⇒ Focus of parabola as (a, 0) i.e. (4, 0) Now, tangents are drawn from (4, 0) to (x − 6) 2 + y 2 = 2. Since, P A is tangent to circle. ∴ t a n θ = slope of tangent = A C A P = √ 2 √ 2 = 1, or B C B P = − 1. ∴ Slope of focal chord as tangent to circle ... phim taxi driver 2 motphim https://asloutdoorstore.com

A focal chord to parabola y^2=16x is a tangent to circle …

WebFocal chord of the parabola is tangent to the circle (x − 6) 2 + y 2 = 2. 2 and ( 6 , 0 ) are radius and centre of the circle As radius is perpendicular to the tangent, we have length of tangent from ( 4 , 0 ) to the circle is = 2 . WebOct 14, 2024 · The focal chord to y^2 =16x is tangent to (x–6)^2 +y2 = 2, then the possible value of the slope of this chord, are asked Oct 22, 2024 in Parabola by deepikaben ( … WebFocal chord to y2=16x is tangent to x−62+y2=2 then the. Focal chord to y2 =16x is tangent to (x−6)2+y2 =2 then the possible values of the slopes of this chord (s),are. … tsmc split corner

The focal chord to y2=16x is tangent to (x−6)2+y2=2, then the …

Category:The focal chord to y2=16x is tangent to (x−6)2+y2=2, then the …

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Focal chord of y 2 16x is a tangent

Focal chord to y2=16x is tangent to x−62+y2=2 then the

WebFocal chord to y 2=16 x is tangent to x 62+ y 2=2 then the possible values of the slopes of this chords,areA. 1,1B. 2,2C. 2, 1/2D. 2, 1/2 Question Focal chord to y 2 = 16 x i s t a n g e n t t o ( x − 6 ) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are WebJan 23, 2024 · Solution For The focal chord to y2=16x is tangent to (x−6)2+y2=2, then the possible values of the slope of this chord, are The world’s only live instant tutoring platform. About Us Become a Tutor. Filo instant Ask button for chrome browser. Now connect to a tutor anywhere from the web ...

Focal chord of y 2 16x is a tangent

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WebClick here👆to get an answer to your question ️ The focal chord to y ^ 2 = 16 x is tangent to ( x - 6 ) ^ 2 + y ^ 2 = 2 then the possible values of the slope of this chord are Solve Study Textbooks Guides WebA: Here, Circle with center O is having tangents JK, KL and JL. so JA¯≅JB¯ ⇒JA=JB (tangent to circle… question_answer Q: Find the surface area of the cone in terms of it.

WebAny chord through focus is called a focal chord and any chord perpendicular to ... 9 3 x 2 y2 Ex.2 Find the equation of the straight lines joining the foci of the ellipse 1 to the 25 16 x 2 y2 foci of the ... parallel to the line y + 2x = 4. Ex.2 Equation of the tangent to an ellipse 9x2 + 16y2 = 144 passing from (2, 3). ... WebThe focal chord to \( y^{2}=16 x \) is tangent to \( (x-6)^{2}+y^{2}=2 \), then the possible values of theslope of this chord are\( P \)(a) \( \{-1,1\} \)\( ...

WebJan 11, 2024 · The focal chord to y^2 = 16 x is tangent to (x - 6)^2 + y^2 = 2 , then the possible value of the slope of this chord, are. ← Prev Question Next Question →. 0 … WebApr 10, 2024 · Even by your method where it seems you are first finding equation of tangent to the circle and equating it to the focal chord, Given the equation of the circle, taking …

Web2) are the endpoints of a focal chord then t 1 t 2 = −1. (2) Tangents at endpoints of a focal chord are perpendicular and hence intersect on directrix. (3) Length of a focal chord of y2 = 4ax, making an angle αwith the X-axis, is 4acosec2α. (4) If AB is a focal chord of y2 = 4ax, then , where S is the focus. Recall

WebQ.3 Find the equations of the tangents to the parabola y2 = 16x, which are parallel ... y = 2x + 1 (C) 2y = x + 8 (D) y = x + 2 Q.10(a) The slope of the focal chords of the parabola y2 = 16x which are tangents to the circle (x ... [ JEE 2003 (Scr.)] Q.6 The line 2x + 6 y = 2 is a tangent to the curve x2 – 2y2 = 4. The point ... tsmc-sonyWebT is a point on the tangent to a parabola y 2 = 4ax at its point P. TL and TN are the perpendiculars on the focal radius SP and the directrix of the parabola respectively. Then. A. SL = 2 (TN) B. 3 (SL) = 2 (TN) C. ... Let PSQ be the focal chord of … phim taxi driver 2 full hdWebFocal chord to y 2 = 16 x i s t a n g e n t t o (x − 6) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are Q. The focal chord to y 2 = 16 x is tangent to ( x − 6 ) 2 … tsmc sox指数WebMay 20, 2024 · The equation of common tangent to the curves y^2 = 16x and xy = –4, is : ... If one end of a focal chord of the parabola, y^2 = 16x is at (1, 4), then the length of this focal chord is : asked May 18, 2024 in Mathematics by Jagan (21.2k points) jee mains 2024; 0 votes. 1 answer. phim tedWebJan 23, 2024 · Here, the focal chord to y2 =16x is tangent to circle (x−6)2+y2 =2 ⇒ focus of the parabola is (4,0) Now, tangent are drawn from (4,0) to (x−6)2+y2=2 Since, P A is tangent to circle and equals to 2 , (from diagram using distance formula) tanθ= slope of tangent =AP AC = 2 2 =1 or tanθ =BP BC =−1 ∴ Slope of focal chord as tangent to … tsmc spiceWebJan 11, 2024 · The focal chord to `y^2=16x` is tangent to `(x-6)^2+ y^2 =2` then the possible values of the slope of this chord asked Nov 15, 2024 in Parabola by kundansingh ( 95.2k points) class-12 phim tears of the sunWebStep-1 Length of tangent : Given: The focal chord to y 2 = 16 x is tangent to (x – 6) 2 + y 2 = 2. The standard equation of the parabola is: y 2 = 4 a x. Comparing the given … tsmc ssgnp